Eqn 12c Help
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= |
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½ (ex/a – e–x/a) dx |
we can represent this in terms of the antiderivatives (indefinite integrals) and their specified limits as
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= | (a/2) (ex/a + e–x/a) |
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which becomes
(y – a) = (a/2) {(ex/a + e–x/a) – (e0 + e0)}
(y – a) = (a/2) {(ex/a + e–x/a) – 2}
and finally
y = ½ a (ex/a + e–x/a)