Eqn 11d Help
Suppose that p = exp (logeq) = e(raised to the power of logeq)
This would be a typographical nightmare … but there's a much simpler way of looking at it: the equation is telling us that the logarithm of p to the base e is logeq
| • | logep = logeq |
and in even simpler terms
| • | p = q |
So if we exponentiate both sides of x/a = loge {u + √(1+u2)}, we get
| • | exp(x/a) | = exp (loge {u + √(1+u2)}) |
which immediately simplifies to | ||
| ex/a | = u + √(1+u2) | |